7*3^2x=567

Solution for 7*3^2x=567 equation:

7*3^2x=567

We move all terms to the left:

7*3^2x-(567)=0

Wy multiply elements

21x^2-567=0

a = 21; b = 0; c = -567;
Δ = b2-4ac
Δ = 02-4·21·(-567)
Δ = 47628
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{47628}=\sqrt{15876*3}=\sqrt{15876}*\sqrt{3}=126\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126\sqrt{3}}{2*21}=\frac{0-126\sqrt{3}}{42}
=-\frac{126\sqrt{3}}{42}
=-3\sqrt{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126\sqrt{3}}{2*21}=\frac{0+126\sqrt{3}}{42}
=\frac{126\sqrt{3}}{42}
=3\sqrt{3}
$